Sampling

Based on Chapter 7 of ModernDive. Code for Quiz 11.

  1. Load the R Package we will use.
  1. Quiz questions

Question:

7.2.4 in Modern Dive with different sample sizes and repetitions

Modify the code for comparing different sample sizes from the virtual bowl

Segment 1: sample size = 28

1.a) Take 1150 samples of size of 28 instead of 1000 replicates of size 25 from the bowl data set. Assign the output to virtual_samples_28

virtual_samples_28 <- bowl %>% 
  rep_sample_n(size = 28, reps = 1150)
virtual_samples_28
# A tibble: 32,200 x 3
# Groups:   replicate [1,150]
   replicate ball_ID color
       <int>   <int> <chr>
 1         1     292 red  
 2         1    1999 white
 3         1     256 white
 4         1     272 white
 5         1       7 red  
 6         1    1288 red  
 7         1     448 white
 8         1    2152 white
 9         1     457 white
10         1    2292 white
# ... with 32,190 more rows

1.b) Compute resulting 1150 replicates of proportion red

start with virtual_samples_28 THEN group_by replicate THEN create variable red equal to the sum of all the red balls create variable prop_red equal to variable red / 28 Assign the output to virtual_prop_red_28

virtual_prop_red_28 <- virtual_samples_28 %>% 
group_by(replicate) %>% 
summarize(red = sum(color == "red")) %>% 
mutate(prop_red = red / 28)

1.c) Plot distribution of virtual_prop_red_28 via a histogram

use labs to

ggplot(virtual_prop_red_28, aes(x = prop_red)) +
  geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
  labs(x = "Proportion of 28 balls that were red", title = "28") 

Segment 2: sample size = 53

2.a) Take 1150 samples of size of 53 instead of 1000 replicates of size 50. Assign the output to virtual_samples_53

virtual_samples_53 <- bowl %>% 
  rep_sample_n(size = 53, reps = 1150)

2.b) Compute resulting 1150 replicates of proportion red

    virtual_prop_red_53 <- virtual_samples_53 %>% 
      group_by(replicate) %>% 
      summarize(red = sum(color == "red")) %>% 
      mutate(prop_red = red / 53)

2.c) Plot distribution of virtual_prop_red_53 via a histogram

use labs to

    ggplot(virtual_prop_red_53, aes(x = prop_red)) +
      geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
      labs(x = "Proportion of 53 balls that were red", title = "53")

Segment 3: sample size = 118

3.a) Take 1150 samples of size of 118 instead of 1000 replicates of size 50. Assign the output to virtual_samples_118

virtual_samples_118 <- bowl %>% 
  rep_sample_n(size = 118, reps = 1150)

3.b) Compute resulting 1150 replicates of proportion red

    virtual_prop_red_118 <- virtual_samples_118 %>% 
      group_by(replicate) %>% 
      summarize(red = sum(color == "red")) %>% 
      mutate(prop_red = red / 118)

3.c) Plot distribution of virtual_prop_red_118 via a histogram

use labs to

    ggplot(virtual_prop_red_118, aes(x = prop_red)) +
      geom_histogram(binwidth = 0.05, boundary = 0.4, color = "white") +
      labs(x = "Proportion of 118 balls that were red", title = "118") 

Calculate the standard deviations for your three sets of 1150 values of prop_red using the standard deviation

n = 28

 virtual_prop_red_28 %>% 
  summarize(sd = sd(prop_red))
# A tibble: 1 x 1
      sd
   <dbl>
1 0.0917

n = 53

virtual_prop_red_53 %>% 
  summarize(sd = sd(prop_red))
# A tibble: 1 x 1
      sd
   <dbl>
1 0.0644

n = 118

virtual_prop_red_118 %>% 
  summarize(sd = sd(prop_red))
# A tibble: 1 x 1
      sd
   <dbl>
1 0.0422

The distribution with sample size, n = 118, has the smallest standard deviation (spread) around the estimated proportion of red balls.